Since Kotlin was designed to be an intelligent language, its developers wanted to give it the readability advantages of dynamically-typed languages without any of the drawbacks. “Inference” can also be understood to mean “ deduction! ” I can see you’ve been paying attention! Well, as mentioned before, the Kotlin compiler has a feature called type inference.
Kotlin being a statically-typed language, this should raise an error, right? On the first line of code, you didn’t mention a type for the variable. In general, Kotlin strongly encourages us to declare all our variables as immutable (via the val keyword) to make our code as close as possible to the functional programming style, thus limiting notorious side effects.Īll right! But I don’t understand. Your variable will therefore point to a reference in memory, but this can be replaced by another if necessary.
This is the default state for all variables in Java. Var (for variable): The reference of your variable will be mutable, i.e., you will be able to modify the content of your variable even after initialization. In fact, it is simply the equivalent of the final keyword in Java! Your variable will always point to the same reference in memory. Val (for value): The reference of your variable will be immutable, i.e., you will not be able to modify it once you have initialized it. I strongly recommend that you use the Kotlin playground throughout this course, which will let you test code written in Kotlin directly on your browser.Īs you can guess by reading the previous lines of code, we can declare a variable in Kotlin using the keywords val and var: Var question: String = "What's your name?" Val question: String = "What's your name?" The example below shows you three ways to declare a string variable in Kotlin. Well, in Kotlin, the way to declare a variable is a bit different… In Java, you’re probably used to writing code like this: String question = "What's your name?" Let’s start with the basis of Kotlin, namely declaring variables.
0 kommentar(er)
